4x^2-3x=2(x-5)

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Solution for 4x^2-3x=2(x-5) equation: 



4x^2-3x=2(x-5)

We move all terms to the left:

4x^2-3x-(2(x-5))=0



We calculate terms in parentheses: -(2(x-5)), so:

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We get rid of parentheses

4x^2-3x-2x+10=0

We add all the numbers together, and all the variables

4x^2-5x+10=0

a = 4; b = -5; c = +10;
Δ = b2-4ac
Δ = -52-4·4·10
Δ = -135
Delta is less than zero, so there is no solution for the equation

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